4(h+3)+2=2((2h)

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Solution for 4(h+3)+2=2((2h) equation: 



4(h+3)+2=2((2h)

We move all terms to the left:

4(h+3)+2-(2((2h))=0

determiningTheFunctionDomain
4(h+3)-(22h+2=0

We multiply parentheses

4h-(22h+2+12=0

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