4(h+i)-(2h+3i)=

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Solution for 4(h+i)-(2h+3i)= equation:


Simplifying
4(h + i) + -1(2h + 3i) = 0
(h * 4 + i * 4) + -1(2h + 3i) = 0
(4h + 4i) + -1(2h + 3i) = 0
4h + 4i + (2h * -1 + 3i * -1) = 0
4h + 4i + (-2h + -3i) = 0

Reorder the terms:
4h + -2h + 4i + -3i = 0

Combine like terms: 4h + -2h = 2h
2h + 4i + -3i = 0

Combine like terms: 4i + -3i = 1i
2h + 1i = 0

Solving
2h + 1i = 0

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-1i' to each side of the equation.
2h + 1i + -1i = 0 + -1i

Combine like terms: 1i + -1i = 0
2h + 0 = 0 + -1i
2h = 0 + -1i
Remove the zero:
2h = -1i

Divide each side by '2'.
h = -0.5i

Simplifying
h = -0.5i

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