4(h-3)=2h+16

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Solution for 4(h-3)=2h+16 equation: 



4(h-3)=2h+16

We move all terms to the left:

4(h-3)-(2h+16)=0

We multiply parentheses

4h-(2h+16)-12=0

We get rid of parentheses

4h-2h-16-12=0

We add all the numbers together, and all the variables

2h-28=0

We move all terms containing h to the left, all other terms to the right

2h=28

h=28/2

h=14

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