4(h-4)-5(h+1)=0

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Solution for 4(h-4)-5(h+1)=0 equation: 



4(h-4)-5(h+1)=0

We multiply parentheses

4h-5h-16-5=0

We add all the numbers together, and all the variables

-1h-21=0

We move all terms containing h to the left, all other terms to the right

-h=21

h=21/-1

h=-21

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