4(i-3)=2i+7

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Solution for 4(i-3)=2i+7 equation: 



4(i-3)=2i+7

We move all terms to the left:

4(i-3)-(2i+7)=0

We multiply parentheses

4i-(2i+7)-12=0

We get rid of parentheses

4i-2i-7-12=0

We add all the numbers together, and all the variables

2i-19=0

We move all terms containing i to the left, all other terms to the right

2i=19

i=19/2

i=9+1/2

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