4(j+28)=52

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Solution for 4(j+28)=52 equation: 



4(j+28)=52

We move all terms to the left:

4(j+28)-(52)=0

We multiply parentheses

4j+112-52=0

We add all the numbers together, and all the variables

4j+60=0

We move all terms containing j to the left, all other terms to the right

4j=-60

j=-60/4

j=-15

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