4(j+4)+3j=3(28+j)

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Solution for 4(j+4)+3j=3(28+j) equation: 


Simplifying
4(j + 4) + 3j = 3(28 + j)

Reorder the terms:
4(4 + j) + 3j = 3(28 + j)
(4 * 4 + j * 4) + 3j = 3(28 + j)
(16 + 4j) + 3j = 3(28 + j)

Combine like terms: 4j + 3j = 7j
16 + 7j = 3(28 + j)
16 + 7j = (28 * 3 + j * 3)
16 + 7j = (84 + 3j)

Solving
16 + 7j = 84 + 3j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-3j' to each side of the equation.
16 + 7j + -3j = 84 + 3j + -3j

Combine like terms: 7j + -3j = 4j
16 + 4j = 84 + 3j + -3j

Combine like terms: 3j + -3j = 0
16 + 4j = 84 + 0
16 + 4j = 84

Add '-16' to each side of the equation.
16 + -16 + 4j = 84 + -16

Combine like terms: 16 + -16 = 0
0 + 4j = 84 + -16
4j = 84 + -16

Combine like terms: 84 + -16 = 68
4j = 68

Divide each side by '4'.
j = 17

Simplifying
j = 17

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