4(j-1)=10(j+2)

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Solution for 4(j-1)=10(j+2) equation: 



4(j-1)=10(j+2)

We move all terms to the left:

4(j-1)-(10(j+2))=0

We multiply parentheses

4j-(10(j+2))-4=0



We calculate terms in parentheses: -(10(j+2)), so:

10(j+2)

We multiply parentheses

10j+20

Back to the equation:

-(10j+20)



We get rid of parentheses

4j-10j-20-4=0

We add all the numbers together, and all the variables

-6j-24=0

We move all terms containing j to the left, all other terms to the right

-6j=24

j=24/-6

j=-4

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