4(j-78)=40

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Solution for 4(j-78)=40 equation: 



4(j-78)=40

We move all terms to the left:

4(j-78)-(40)=0

We multiply parentheses

4j-312-40=0

We add all the numbers together, and all the variables

4j-352=0

We move all terms containing j to the left, all other terms to the right

4j=352

j=352/4

j=88

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