4(k+1)+3(k-1)=15

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Solution for 4(k+1)+3(k-1)=15 equation: 


Simplifying
4(k + 1) + 3(k + -1) = 15

Reorder the terms:
4(1 + k) + 3(k + -1) = 15
(1 * 4 + k * 4) + 3(k + -1) = 15
(4 + 4k) + 3(k + -1) = 15

Reorder the terms:
4 + 4k + 3(-1 + k) = 15
4 + 4k + (-1 * 3 + k * 3) = 15
4 + 4k + (-3 + 3k) = 15

Reorder the terms:
4 + -3 + 4k + 3k = 15

Combine like terms: 4 + -3 = 1
1 + 4k + 3k = 15

Combine like terms: 4k + 3k = 7k
1 + 7k = 15

Solving
1 + 7k = 15

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 7k = 15 + -1

Combine like terms: 1 + -1 = 0
0 + 7k = 15 + -1
7k = 15 + -1

Combine like terms: 15 + -1 = 14
7k = 14

Divide each side by '7'.
k = 2

Simplifying
k = 2

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