4(k+3)-2(k-3)=38

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Solution for 4(k+3)-2(k-3)=38 equation: 



4(k+3)-2(k-3)=38

We move all terms to the left:

4(k+3)-2(k-3)-(38)=0

We multiply parentheses

4k-2k+12+6-38=0

We add all the numbers together, and all the variables

2k-20=0

We move all terms containing k to the left, all other terms to the right

2k=20

k=20/2

k=10

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