4(k+3)=2(k+6)+20

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Solution for 4(k+3)=2(k+6)+20 equation: 



4(k+3)=2(k+6)+20

We move all terms to the left:

4(k+3)-(2(k+6)+20)=0

We multiply parentheses

4k-(2(k+6)+20)+12=0



We calculate terms in parentheses: -(2(k+6)+20), so:

2(k+6)+20

We multiply parentheses

2k+12+20

We add all the numbers together, and all the variables

2k+32

Back to the equation:

-(2k+32)



We get rid of parentheses

4k-2k-32+12=0

We add all the numbers together, and all the variables

2k-20=0

We move all terms containing k to the left, all other terms to the right

2k=20

k=20/2

k=10

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