4(k+3)=28*

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Solution for 4(k+3)=28* equation: 



4(k+3)=28*

We move all terms to the left:

4(k+3)-(28*)=0

We add all the numbers together, and all the variables

4(k+3)-0=0

We add all the numbers together, and all the variables

4(k+3)=0

We multiply parentheses

4k+12=0

We move all terms containing k to the left, all other terms to the right

4k=-12

k=-12/4

k=-3

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