4(k+4)+11=3(k+10)+k-3

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Solution for 4(k+4)+11=3(k+10)+k-3 equation: 



4(k+4)+11=3(k+10)+k-3

We move all terms to the left:

4(k+4)+11-(3(k+10)+k-3)=0

We multiply parentheses

4k-(3(k+10)+k-3)+16+11=0



We calculate terms in parentheses: -(3(k+10)+k-3), so:

3(k+10)+k-3

We add all the numbers together, and all the variables

k+3(k+10)-3

We multiply parentheses

k+3k+30-3

We add all the numbers together, and all the variables

4k+27

Back to the equation:

-(4k+27)



We add all the numbers together, and all the variables

4k-(4k+27)+27=0

We get rid of parentheses

4k-4k-27+27=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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