4(k+4)-8(k+4)=5(3k-4)-9(3k+4)

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Solution for 4(k+4)-8(k+4)=5(3k-4)-9(3k+4) equation: 



4(k+4)-8(k+4)=5(3k-4)-9(3k+4)

We move all terms to the left:

4(k+4)-8(k+4)-(5(3k-4)-9(3k+4))=0

We multiply parentheses

4k-8k-(5(3k-4)-9(3k+4))+16-32=0



We calculate terms in parentheses: -(5(3k-4)-9(3k+4)), so:

5(3k-4)-9(3k+4)

We multiply parentheses

15k-27k-20-36

We add all the numbers together, and all the variables

-12k-56

Back to the equation:

-(-12k-56)



We add all the numbers together, and all the variables

-4k-(-12k-56)-16=0

We get rid of parentheses

-4k+12k+56-16=0

We add all the numbers together, and all the variables

8k+40=0

We move all terms containing k to the left, all other terms to the right

8k=-40

k=-40/8

k=-5

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