4(k+5)-2+6=2(3k+2)-6

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Solution for 4(k+5)-2+6=2(3k+2)-6 equation: 



4(k+5)-2+6=2(3k+2)-6

We move all terms to the left:

4(k+5)-2+6-(2(3k+2)-6)=0

We add all the numbers together, and all the variables

4(k+5)-(2(3k+2)-6)+4=0

We multiply parentheses

4k-(2(3k+2)-6)+20+4=0



We calculate terms in parentheses: -(2(3k+2)-6), so:

2(3k+2)-6

We multiply parentheses

6k+4-6

We add all the numbers together, and all the variables

6k-2

Back to the equation:

-(6k-2)



We add all the numbers together, and all the variables

4k-(6k-2)+24=0

We get rid of parentheses

4k-6k+2+24=0

We add all the numbers together, and all the variables

-2k+26=0

We move all terms containing k to the left, all other terms to the right

-2k=-26

k=-26/-2

k=+13

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