4(k+6)=2(k-3)+4k

Solution for 4(k+6)=2(k-3)+4k equation:

4(k+6)=2(k-3)+4k

We move all terms to the left:

4(k+6)-(2(k-3)+4k)=0

We multiply parentheses

4k-(2(k-3)+4k)+24=0


We calculate terms in parentheses: -(2(k-3)+4k), so:

2(k-3)+4k

We add all the numbers together, and all the variables

4k+2(k-3)

We multiply parentheses

4k+2k-6

We add all the numbers together, and all the variables

6k-6

Back to the equation:

-(6k-6)


We get rid of parentheses

4k-6k+6+24=0

We add all the numbers together, and all the variables

-2k+30=0

We move all terms containing k to the left, all other terms to the right

-2k=-30

k=-30/-2

k=+15