4(k+7)=2k+32

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Solution for 4(k+7)=2k+32 equation: 



4(k+7)=2k+32

We move all terms to the left:

4(k+7)-(2k+32)=0

We multiply parentheses

4k-(2k+32)+28=0

We get rid of parentheses

4k-2k-32+28=0

We add all the numbers together, and all the variables

2k-4=0

We move all terms containing k to the left, all other terms to the right

2k=4

k=4/2

k=2

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