4(k-1)=2(k-5)

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Solution for 4(k-1)=2(k-5) equation: 



4(k-1)=2(k-5)

We move all terms to the left:

4(k-1)-(2(k-5))=0

We multiply parentheses

4k-(2(k-5))-4=0



We calculate terms in parentheses: -(2(k-5)), so:

2(k-5)

We multiply parentheses

2k-10

Back to the equation:

-(2k-10)



We get rid of parentheses

4k-2k+10-4=0

We add all the numbers together, and all the variables

2k+6=0

We move all terms containing k to the left, all other terms to the right

2k=-6

k=-6/2

k=-3

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