4(k-11)=3

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Solution for 4(k-11)=3 equation: 



4(k-11)=3

We move all terms to the left:

4(k-11)-(3)=0

We multiply parentheses

4k-44-3=0

We add all the numbers together, and all the variables

4k-47=0

We move all terms containing k to the left, all other terms to the right

4k=47

k=47/4

k=11+3/4

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