4(k-2)=2(k+2)

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Solution for 4(k-2)=2(k+2) equation: 



4(k-2)=2(k+2)

We move all terms to the left:

4(k-2)-(2(k+2))=0

We multiply parentheses

4k-(2(k+2))-8=0



We calculate terms in parentheses: -(2(k+2)), so:

2(k+2)

We multiply parentheses

2k+4

Back to the equation:

-(2k+4)



We get rid of parentheses

4k-2k-4-8=0

We add all the numbers together, and all the variables

2k-12=0

We move all terms containing k to the left, all other terms to the right

2k=12

k=12/2

k=6

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