4(k-3)+(k-3)=2(k-5)

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Solution for 4(k-3)+(k-3)=2(k-5) equation:


4(k-3)+(k-3)=2(k-5)

We simplify the equation to the form, which is simple to understand
4(k-3)+(k-3)=2(k-5)

Reorder the terms in parentheses
+(+4k-12)+(k-3)=2*(k-5)

Remove unnecessary parentheses
+4k-12+(+k-3+)=+2+*(+k-5+)

Remove unnecessary parentheses
+4k-12+k-3=+2+*(+k-5+)

Reorder the terms in parentheses
+4k-12k-3=+(+2k-10)

Remove unnecessary parentheses
+4k-12+k-3=+2k-10

We move all terms containing k to the left and all other terms to the right.
+4k+1k-2k=-10+12+3

We simplify left and right side of the equation.
+3k=+5

We divide both sides of the equation by 3 to get k.
k=1.66666666667

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