4(k-3)+7=2k-(k=8)

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Solution for 4(k-3)+7=2k-(k=8) equation: 



4(k-3)+7=2k-(k=8)

We move all terms to the left:

4(k-3)+7-(2k-(k)=0

We multiply parentheses

4k-(2k-k+7-12=0

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