4(k-3)+8k=-6(2+7k)

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Solution for 4(k-3)+8k=-6(2+7k) equation: 



4(k-3)+8k=-6(2+7k)

We move all terms to the left:

4(k-3)+8k-(-6(2+7k))=0

We add all the numbers together, and all the variables

4(k-3)+8k-(-6(7k+2))=0

We add all the numbers together, and all the variables

8k+4(k-3)-(-6(7k+2))=0

We multiply parentheses

8k+4k-(-6(7k+2))-12=0



We calculate terms in parentheses: -(-6(7k+2)), so:

-6(7k+2)

We multiply parentheses

-42k-12

Back to the equation:

-(-42k-12)



We add all the numbers together, and all the variables

12k-(-42k-12)-12=0

We get rid of parentheses

12k+42k+12-12=0

We add all the numbers together, and all the variables

54k=0

k=0/54

k=0

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