4(k-3)-6=4k-(3k-1)

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Solution for 4(k-3)-6=4k-(3k-1) equation: 



4(k-3)-6=4k-(3k-1)

We move all terms to the left:

4(k-3)-6-(4k-(3k-1))=0

We multiply parentheses

4k-(4k-(3k-1))-12-6=0



We calculate terms in parentheses: -(4k-(3k-1)), so:

4k-(3k-1)

We get rid of parentheses

4k-3k+1

We add all the numbers together, and all the variables

k+1

Back to the equation:

-(k+1)



We add all the numbers together, and all the variables

4k-(k+1)-18=0

We get rid of parentheses

4k-k-1-18=0

We add all the numbers together, and all the variables

3k-19=0

We move all terms containing k to the left, all other terms to the right

3k=19

k=19/3

k=6+1/3

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