4(k-3)-7=3k-(2k-3)

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Solution for 4(k-3)-7=3k-(2k-3) equation: 



4(k-3)-7=3k-(2k-3)

We move all terms to the left:

4(k-3)-7-(3k-(2k-3))=0

We multiply parentheses

4k-(3k-(2k-3))-12-7=0



We calculate terms in parentheses: -(3k-(2k-3)), so:

3k-(2k-3)

We get rid of parentheses

3k-2k+3

We add all the numbers together, and all the variables

k+3

Back to the equation:

-(k+3)



We add all the numbers together, and all the variables

4k-(k+3)-19=0

We get rid of parentheses

4k-k-3-19=0

We add all the numbers together, and all the variables

3k-22=0

We move all terms containing k to the left, all other terms to the right

3k=22

k=22/3

k=7+1/3

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