4(k-3)-7=5k-(4k-3)

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Solution for 4(k-3)-7=5k-(4k-3) equation:



4(k-3)-7=5k-(4k-3)
We move all terms to the left:
4(k-3)-7-(5k-(4k-3))=0
We multiply parentheses
4k-(5k-(4k-3))-12-7=0
We calculate terms in parentheses: -(5k-(4k-3)), so:
5k-(4k-3)
We get rid of parentheses
5k-4k+3
We add all the numbers together, and all the variables
k+3
Back to the equation:
-(k+3)
We add all the numbers together, and all the variables
4k-(k+3)-19=0
We get rid of parentheses
4k-k-3-19=0
We add all the numbers together, and all the variables
3k-22=0
We move all terms containing k to the left, all other terms to the right
3k=22
k=22/3
k=7+1/3

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