4(k-3)=-(12-4k)

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Solution for 4(k-3)=-(12-4k) equation: 



4(k-3)=-(12-4k)

We move all terms to the left:

4(k-3)-(-(12-4k))=0

We add all the numbers together, and all the variables

4(k-3)-(-(-4k+12))=0

We multiply parentheses

4k-(-(-4k+12))-12=0



We calculate terms in parentheses: -(-(-4k+12)), so:

-(-4k+12)

We get rid of parentheses

4k-12

Back to the equation:

-(4k-12)



We get rid of parentheses

4k-4k+12-12=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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