4(k-3)=2(2k-6)

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Solution for 4(k-3)=2(2k-6) equation:


Simplifying
4(k + -3) = 2(2k + -6)

Reorder the terms:
4(-3 + k) = 2(2k + -6)
(-3 * 4 + k * 4) = 2(2k + -6)
(-12 + 4k) = 2(2k + -6)

Reorder the terms:
-12 + 4k = 2(-6 + 2k)
-12 + 4k = (-6 * 2 + 2k * 2)
-12 + 4k = (-12 + 4k)

Add '12' to each side of the equation.
-12 + 12 + 4k = -12 + 12 + 4k

Combine like terms: -12 + 12 = 0
0 + 4k = -12 + 12 + 4k
4k = -12 + 12 + 4k

Combine like terms: -12 + 12 = 0
4k = 0 + 4k
4k = 4k

Add '-4k' to each side of the equation.
4k + -4k = 4k + -4k

Combine like terms: 4k + -4k = 0
0 = 4k + -4k

Combine like terms: 4k + -4k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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