4(k-3)=2(k-2)

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Solution for 4(k-3)=2(k-2) equation: 



4(k-3)=2(k-2)

We move all terms to the left:

4(k-3)-(2(k-2))=0

We multiply parentheses

4k-(2(k-2))-12=0



We calculate terms in parentheses: -(2(k-2)), so:

2(k-2)

We multiply parentheses

2k-4

Back to the equation:

-(2k-4)



We get rid of parentheses

4k-2k+4-12=0

We add all the numbers together, and all the variables

2k-8=0

We move all terms containing k to the left, all other terms to the right

2k=8

k=8/2

k=4

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