4(k-3)=2-(2k-)

Solution for 4(k-3)=2-(2k-) equation:

4(k-3)=2-(2k-)

We move all terms to the left:

4(k-3)-(2-(2k-))=0

We add all the numbers together, and all the variables

4(k-3)-(2-(+2k))=0

We multiply parentheses

4k-(2-(+2k))-12=0


We calculate terms in parentheses: -(2-(+2k)), so:

2-(+2k)

determiningTheFunctionDomain
-(+2k)+2

We get rid of parentheses

-2k+2

Back to the equation:

-(-2k+2)


We get rid of parentheses

4k+2k-2-12=0

We add all the numbers together, and all the variables

6k-14=0

We move all terms containing k to the left, all other terms to the right

6k=14

k=14/6

k=2+1/3