4(k-4)-3(k+1)-13=-26

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Solution for 4(k-4)-3(k+1)-13=-26 equation: 



4(k-4)-3(k+1)-13=-26

We move all terms to the left:

4(k-4)-3(k+1)-13-(-26)=0

We add all the numbers together, and all the variables

4(k-4)-3(k+1)+13=0

We multiply parentheses

4k-3k-16-3+13=0

We add all the numbers together, and all the variables

k-6=0

We move all terms containing k to the left, all other terms to the right

k=6

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