4(k-4)=8(k-1)

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Solution for 4(k-4)=8(k-1) equation: 



4(k-4)=8(k-1)

We move all terms to the left:

4(k-4)-(8(k-1))=0

We multiply parentheses

4k-(8(k-1))-16=0



We calculate terms in parentheses: -(8(k-1)), so:

8(k-1)

We multiply parentheses

8k-8

Back to the equation:

-(8k-8)



We get rid of parentheses

4k-8k+8-16=0

We add all the numbers together, and all the variables

-4k-8=0

We move all terms containing k to the left, all other terms to the right

-4k=8

k=8/-4

k=-2

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