4(k-5)-8k=-2(3k+1)

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Solution for 4(k-5)-8k=-2(3k+1) equation: 



4(k-5)-8k=-2(3k+1)

We move all terms to the left:

4(k-5)-8k-(-2(3k+1))=0

We add all the numbers together, and all the variables

-8k+4(k-5)-(-2(3k+1))=0

We multiply parentheses

-8k+4k-(-2(3k+1))-20=0



We calculate terms in parentheses: -(-2(3k+1)), so:

-2(3k+1)

We multiply parentheses

-6k-2

Back to the equation:

-(-6k-2)



We add all the numbers together, and all the variables

-4k-(-6k-2)-20=0

We get rid of parentheses

-4k+6k+2-20=0

We add all the numbers together, and all the variables

2k-18=0

We move all terms containing k to the left, all other terms to the right

2k=18

k=18/2

k=9

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