4(k-6)-3(3k-11)=12

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Solution for 4(k-6)-3(3k-11)=12 equation:


Simplifying
4(k + -6) + -3(3k + -11) = 12

Reorder the terms:
4(-6 + k) + -3(3k + -11) = 12
(-6 * 4 + k * 4) + -3(3k + -11) = 12
(-24 + 4k) + -3(3k + -11) = 12

Reorder the terms:
-24 + 4k + -3(-11 + 3k) = 12
-24 + 4k + (-11 * -3 + 3k * -3) = 12
-24 + 4k + (33 + -9k) = 12

Reorder the terms:
-24 + 33 + 4k + -9k = 12

Combine like terms: -24 + 33 = 9
9 + 4k + -9k = 12

Combine like terms: 4k + -9k = -5k
9 + -5k = 12

Solving
9 + -5k = 12

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -5k = 12 + -9

Combine like terms: 9 + -9 = 0
0 + -5k = 12 + -9
-5k = 12 + -9

Combine like terms: 12 + -9 = 3
-5k = 3

Divide each side by '-5'.
k = -0.6

Simplifying
k = -0.6

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