4(k-6)=(k+12)

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Solution for 4(k-6)=(k+12) equation: 



4(k-6)=(k+12)

We move all terms to the left:

4(k-6)-((k+12))=0

We multiply parentheses

4k-((k+12))-24=0



We calculate terms in parentheses: -((k+12)), so:

(k+12)

We get rid of parentheses

k+12

Back to the equation:

-(k+12)



We get rid of parentheses

4k-k-12-24=0

We add all the numbers together, and all the variables

3k-36=0

We move all terms containing k to the left, all other terms to the right

3k=36

k=36/3

k=12

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