4(ln(3x)+1)=28

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Solution for 4(ln(3x)+1)=28 equation:


Simplifying
4(ln(3x) + 1) = 28

Remove parenthesis around (3x)
4(ln * 3x + 1) = 28

Reorder the terms for easier multiplication:
4(3ln * x + 1) = 28

Multiply ln * x
4(3lnx + 1) = 28

Reorder the terms:
4(1 + 3lnx) = 28
(1 * 4 + 3lnx * 4) = 28
(4 + 12lnx) = 28

Solving
4 + 12lnx = 28

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 12lnx = 28 + -4

Combine like terms: 4 + -4 = 0
0 + 12lnx = 28 + -4
12lnx = 28 + -4

Combine like terms: 28 + -4 = 24
12lnx = 24

Divide each side by '12nx'.
l = 2n-1x-1

Simplifying
l = 2n-1x-1

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