4(m+-33)=-80

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Solution for 4(m+-33)=-80 equation: 



4(m+-33)=-80

We move all terms to the left:

4(m+-33)-(-80)=0

We add all the numbers together, and all the variables

4(m-33)-(-80)=0

We add all the numbers together, and all the variables

4(m-33)+80=0

We multiply parentheses

4m-132+80=0

We add all the numbers together, and all the variables

4m-52=0

We move all terms containing m to the left, all other terms to the right

4m=52

m=52/4

m=13

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