4(m+1)=4(2-m)

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Solution for 4(m+1)=4(2-m) equation: 



4(m+1)=4(2-m)

We move all terms to the left:

4(m+1)-(4(2-m))=0

We add all the numbers together, and all the variables

4(m+1)-(4(-1m+2))=0

We multiply parentheses

4m-(4(-1m+2))+4=0



We calculate terms in parentheses: -(4(-1m+2)), so:

4(-1m+2)

We multiply parentheses

-4m+8

Back to the equation:

-(-4m+8)



We get rid of parentheses

4m+4m-8+4=0

We add all the numbers together, and all the variables

8m-4=0

We move all terms containing m to the left, all other terms to the right

8m=4

m=4/8

m=1/2

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