4(m+12)+4=20

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Solution for 4(m+12)+4=20 equation: 



4(m+12)+4=20

We move all terms to the left:

4(m+12)+4-(20)=0

We add all the numbers together, and all the variables

4(m+12)-16=0

We multiply parentheses

4m+48-16=0

We add all the numbers together, and all the variables

4m+32=0

We move all terms containing m to the left, all other terms to the right

4m=-32

m=-32/4

m=-8

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