4(m+12)=20

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Solution for 4(m+12)=20 equation: 



4(m+12)=20

We move all terms to the left:

4(m+12)-(20)=0

We multiply parentheses

4m+48-20=0

We add all the numbers together, and all the variables

4m+28=0

We move all terms containing m to the left, all other terms to the right

4m=-28

m=-28/4

m=-7

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