4(m+2)+7=6(m+1)+2

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Solution for 4(m+2)+7=6(m+1)+2 equation: 



4(m+2)+7=6(m+1)+2

We move all terms to the left:

4(m+2)+7-(6(m+1)+2)=0

We multiply parentheses

4m-(6(m+1)+2)+8+7=0



We calculate terms in parentheses: -(6(m+1)+2), so:

6(m+1)+2

We multiply parentheses

6m+6+2

We add all the numbers together, and all the variables

6m+8

Back to the equation:

-(6m+8)



We add all the numbers together, and all the variables

4m-(6m+8)+15=0

We get rid of parentheses

4m-6m-8+15=0

We add all the numbers together, and all the variables

-2m+7=0

We move all terms containing m to the left, all other terms to the right

-2m=-7

m=-7/-2

m=3+1/2

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