4(m+2)+m=20+2m

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Solution for 4(m+2)+m=20+2m equation: 



4(m+2)+m=20+2m

We move all terms to the left:

4(m+2)+m-(20+2m)=0

We add all the numbers together, and all the variables

4(m+2)+m-(2m+20)=0

We add all the numbers together, and all the variables

m+4(m+2)-(2m+20)=0

We multiply parentheses

m+4m-(2m+20)+8=0

We get rid of parentheses

m+4m-2m-20+8=0

We add all the numbers together, and all the variables

3m-12=0

We move all terms containing m to the left, all other terms to the right

3m=12

m=12/3

m=4

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