4(m+2)=(2m-1)

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Solution for 4(m+2)=(2m-1) equation: 



4(m+2)=(2m-1)

We move all terms to the left:

4(m+2)-((2m-1))=0

We multiply parentheses

4m-((2m-1))+8=0



We calculate terms in parentheses: -((2m-1)), so:

(2m-1)

We get rid of parentheses

2m-1

Back to the equation:

-(2m-1)



We get rid of parentheses

4m-2m+1+8=0

We add all the numbers together, and all the variables

2m+9=0

We move all terms containing m to the left, all other terms to the right

2m=-9

m=-9/2

m=-4+1/2

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