4(m+3)=2(m-10)

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Solution for 4(m+3)=2(m-10) equation: 



4(m+3)=2(m-10)

We move all terms to the left:

4(m+3)-(2(m-10))=0

We multiply parentheses

4m-(2(m-10))+12=0



We calculate terms in parentheses: -(2(m-10)), so:

2(m-10)

We multiply parentheses

2m-20

Back to the equation:

-(2m-20)



We get rid of parentheses

4m-2m+20+12=0

We add all the numbers together, and all the variables

2m+32=0

We move all terms containing m to the left, all other terms to the right

2m=-32

m=-32/2

m=-16

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