4(m+3)=2(m-10)

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Solution for 4(m+3)=2(m-10) equation:



4(m+3)=2(m-10)
We move all terms to the left:
4(m+3)-(2(m-10))=0
We multiply parentheses
4m-(2(m-10))+12=0
We calculate terms in parentheses: -(2(m-10)), so:
2(m-10)
We multiply parentheses
2m-20
Back to the equation:
-(2m-20)
We get rid of parentheses
4m-2m+20+12=0
We add all the numbers together, and all the variables
2m+32=0
We move all terms containing m to the left, all other terms to the right
2m=-32
m=-32/2
m=-16

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