4(m+3)=3(m+4)+m

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Solution for 4(m+3)=3(m+4)+m equation:


Simplifying
4(m + 3) = 3(m + 4) + m

Reorder the terms:
4(3 + m) = 3(m + 4) + m
(3 * 4 + m * 4) = 3(m + 4) + m
(12 + 4m) = 3(m + 4) + m

Reorder the terms:
12 + 4m = 3(4 + m) + m
12 + 4m = (4 * 3 + m * 3) + m
12 + 4m = (12 + 3m) + m

Combine like terms: 3m + m = 4m
12 + 4m = 12 + 4m

Add '-12' to each side of the equation.
12 + -12 + 4m = 12 + -12 + 4m

Combine like terms: 12 + -12 = 0
0 + 4m = 12 + -12 + 4m
4m = 12 + -12 + 4m

Combine like terms: 12 + -12 = 0
4m = 0 + 4m
4m = 4m

Add '-4m' to each side of the equation.
4m + -4m = 4m + -4m

Combine like terms: 4m + -4m = 0
0 = 4m + -4m

Combine like terms: 4m + -4m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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