4(m+3)=4m+12

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Solution for 4(m+3)=4m+12 equation: 


Simplifying
4(m + 3) = 4m + 12

Reorder the terms:
4(3 + m) = 4m + 12
(3 * 4 + m * 4) = 4m + 12
(12 + 4m) = 4m + 12

Reorder the terms:
12 + 4m = 12 + 4m

Add '-12' to each side of the equation.
12 + -12 + 4m = 12 + -12 + 4m

Combine like terms: 12 + -12 = 0
0 + 4m = 12 + -12 + 4m
4m = 12 + -12 + 4m

Combine like terms: 12 + -12 = 0
4m = 0 + 4m
4m = 4m

Add '-4m' to each side of the equation.
4m + -4m = 4m + -4m

Combine like terms: 4m + -4m = 0
0 = 4m + -4m

Combine like terms: 4m + -4m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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