4(m+4)=-4m+12(-12-6m)

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Solution for 4(m+4)=-4m+12(-12-6m) equation: 



4(m+4)=-4m+12(-12-6m)

We move all terms to the left:

4(m+4)-(-4m+12(-12-6m))=0

We add all the numbers together, and all the variables

4(m+4)-(-4m+12(-6m-12))=0

We multiply parentheses

4m-(-4m+12(-6m-12))+16=0



We calculate terms in parentheses: -(-4m+12(-6m-12)), so:

-4m+12(-6m-12)

We multiply parentheses

-4m-72m-144

We add all the numbers together, and all the variables

-76m-144

Back to the equation:

-(-76m-144)



We get rid of parentheses

4m+76m+144+16=0

We add all the numbers together, and all the variables

80m+160=0

We move all terms containing m to the left, all other terms to the right

80m=-160

m=-160/80

m=-2

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