4(m+n)+2(2m+n)=

Solution for 4(m+n)+2(2m+n)= equation:

Simplifying
4(m + n) + 2(2m + n) = 0
(m * 4 + n * 4) + 2(2m + n) = 0
(4m + 4n) + 2(2m + n) = 0
4m + 4n + (2m * 2 + n * 2) = 0
4m + 4n + (4m + 2n) = 0

Reorder the terms:
4m + 4m + 4n + 2n = 0

Combine like terms: 4m + 4m = 8m
8m + 4n + 2n = 0

Combine like terms: 4n + 2n = 6n
8m + 6n = 0

Solving
8m + 6n = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-6n' to each side of the equation.
8m + 6n + -6n = 0 + -6n

Combine like terms: 6n + -6n = 0
8m + 0 = 0 + -6n
8m = 0 + -6n
Remove the zero:
8m = -6n

Divide each side by '8'.
m = -0.75n

Simplifying
m = -0.75n