4(m-1)+5=1+6(4-5m)

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Solution for 4(m-1)+5=1+6(4-5m) equation: 



4(m-1)+5=1+6(4-5m)

We move all terms to the left:

4(m-1)+5-(1+6(4-5m))=0

We add all the numbers together, and all the variables

4(m-1)-(1+6(-5m+4))+5=0

We multiply parentheses

4m-(1+6(-5m+4))-4+5=0



We calculate terms in parentheses: -(1+6(-5m+4)), so:

1+6(-5m+4)

determiningTheFunctionDomain
6(-5m+4)+1

We multiply parentheses

-30m+24+1

We add all the numbers together, and all the variables

-30m+25

Back to the equation:

-(-30m+25)



We add all the numbers together, and all the variables

4m-(-30m+25)+1=0

We get rid of parentheses

4m+30m-25+1=0

We add all the numbers together, and all the variables

34m-24=0

We move all terms containing m to the left, all other terms to the right

34m=24

m=24/34

m=12/17

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